6a^2+12a+2=0

Solution for 6a^2+12a+2=0 equation:

6a^2+12a+2=0

a = 6; b = 12; c = +2;
Δ = b2-4ac
Δ = 122-4·6·2
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{6}}{2*6}=\frac{-12-4\sqrt{6}}{12}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{6}}{2*6}=\frac{-12+4\sqrt{6}}{12}
$